Q. If $\left| \begin{array}{r} 6i\ - 3i\ \ \ \ \ 1 \\ 4\ \ \ \ \ 3i\ \ - 1 \\ 40\ \ \ \ \ \ 3\ \ \ \ \ \ \ i \end{array} \right|$= $x + iy,$ then
A) $x = 3,y = 1$
B) $x = 1,\ y = 3$
C) $x = 0,y = 3$
D) $x = 0,y = 0$
Explanation
(d)
$x + iy$ = $- 3i\left| \begin{array}{r}
6i\ \ \ \ \ \ \ 1\ \ \ \ \ \ 1 \\
4\ \ \ \ - 1\ - 1 \\
20\ \ \ \ \ \ i\ \ \ \ \ \ \ i
\end{array} \right| = 0$
$\Rightarrow \ \ x = 0,\ \ y = 0$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.