Q. The value of the determinant $\mathrm{\Delta} = \left| \begin{matrix} 2a_{1}b_{1} & a_{1}b_{2} + a_{2}b_{1} & a_{1}b_{3} + a_{3}b_{1} \\ a_{1}b_{2} + a_{2}b_{1} & 2a_{2}b_{2} & a_{2}b_{3} + a_{3}b_{2} \\ a_{1}b_{3} + a_{3}b_{1} & a_{3}b_{2} + a_{2}b_{3} & 2a_{3}b_{3} \end{matrix} \right|$ is

A) 1
B) $2a_{1}a_{2}a_{3}b_{1}b_{2}b_{3}$
C) 0
D) $a_{1}a_{2}a_{3}b_{1}b_{2}b_{3}$
Explanation

(c)
We have,
$\mathrm{\Delta} = \left| \begin{matrix}
2a_{1}b_{1} & a_{1}b_{2} + a_{2}b_{1} & a_{1}b_{3} + a_{3}b_{1} \\
a_{1}b_{2} + a_{2}b_{1} & 2a_{2}b_{2} & a_{2}b_{3} + a_{3}b_{2} \\
a_{1}b_{3} + a_{3}b_{1} & a_{3}b_{2} + a_{2}b_{3} & 2a_{3}b_{3}
\end{matrix} \right|$
This can be written as
$\left| \begin{matrix}
a_{1} & b_{1} & 0 \\
a_{2} & b_{2} & 0 \\
a_{3} & b_{3} & 0
\end{matrix} \right|\left| \begin{matrix}
b_{1} & a_{1} & 0 \\
b_{2} & a_{2} & 0 \\
b_{3} & a_{3} & 0
\end{matrix} \right| = 0$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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