Q. If $x,\ y,\ z$ are different from zero and $\mathrm{\Delta}\left| \begin{matrix} a & b - y & c - z \\ a - x & b & c - z \\ a - x & b - y & c \end{matrix} \right| = 0,$ then the value of the expression $\frac{a}{x} + \frac{b}{y} + \frac{c}{z}$ is

A) 0
B) $- 1$
C) 1
D) 2
Explanation

(d)
$\left| \begin{matrix}
a & b - y & c - z \\
a - x & b & c - z \\
a - x & b - y & c
\end{matrix} \right|$=0
$\Rightarrow \left| \begin{matrix}
a & b - y & c - z \\
- x & y & 0 \\
0 & - y & z
\end{matrix} \right|$=0
(Using $R_{2} \rightarrow R_{2} - R_{1}\$and$\ R_{3} \rightarrow R_{3} - R_{2})$
$\Rightarrow a(yz) + x(bz - yz + cy - yz) = 0$
$\Rightarrow ayz + bzx + cyx = 2xyz$
$\Rightarrow \frac{a}{x} + \frac{b}{y} + \frac{c}{z} = 2$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

Want more practice?
Practice Determinants MCQs