(d) Applying $C_{2} \rightarrow C_{2} - C_{1},\ C_{3} \rightarrow C_{3} - C_{2}$, we get $\left| \begin{matrix} 1990 & 1 & 1 \\ 1991 & 1 & 1 \\ 1992 & 1 & 1 \end{matrix} \right| = 0$
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.