Q. The value of the following determinant is $\mathrm{\Delta} = \left| \begin{matrix} 1 & 1 & 1 \\ a & b & c \\ a^{3} & b^{3} & c^{3} \end{matrix} \right|$

A) $(a - b)(b - c)(c - a)(a + b + c)$
B) $abc(a + b)(b + c)(c + a)$
C) $(a - b)(b - c)(c - a)$
D) None of the above
Explanation

(a)
Given, $\mathrm{\Delta} = \left| \begin{matrix}
1 & 1 & 1 \\
a & b & c \\
a^{3} & b^{3} & c^{3}
\end{matrix} \right| = \left| \begin{matrix}
1 & 0 & 0 \\
a & a - b & a - c \\
a^{3} & a^{3} - b^{3} & a^{3} - c^{3}
\end{matrix} \right|$
$\lbrack C_{2} \rightarrow C_{1} - C_{2},C_{3} \rightarrow C_{1} - C_{3}\rbrack$
$= (a - b)(a - c)\ \left| \begin{matrix}
1 & 0 & 0 \\
a & 1 & 1 \\
a^{3} & a^{2} + ab + b^{2} & a^{2} + ac + c^{2}
\end{matrix} \right|$
$= (a - b)(a - c)(c^{2} + ac - ab - b^{2})$
$= (a - b)(b - c)(c - a)(a + b + c)$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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