Q. If $\left| \begin{array}{r} - 12\ \ \ \ \ 0\ \ \ \ \ \ \ \ \ \lambda \\ 0\ \ \ \ \ \ \ 2\ \ \ \ - 1 \\ 2\ \ \ \ \ \ \ 1\ \ \ \ \ \ \ 15 \end{array} \right| = - 360,\$then the value of $\lambda$ is

A) $- 1$
B) $- 2$
C) $- 3$
D) 4
Explanation

(c)
$\left| \begin{array}{r}
- 12\ \ \ \ \ 0\ \ \ \ \ \ \ \ \ \lambda \\
0\ \ \ \ \ \ \ 2\ \ \ \ - 1 \\
2\ \ \ \ \ \ \ 1\ \ \ \ \ \ \ 15
\end{array} \right|$=-360
$\Rightarrow \ \ - 12(30 + 1) - 4\lambda = - 360$
$\Rightarrow \ \ \ - 372 + 360 = 4\ \lambda\ \ \Rightarrow \ \ \ \lambda = - \frac{12}{4} = - 3$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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