If $a,b,c$ are different, then the value of $x$ satisfying $\left| \begin{matrix} 0 & x^{2} - a & x^{3} - b \ x^{2} + a & 0 & x^{2} + c \ x^{4} + a & x - c & 0 \end{matrix} ight| = 0$ is

Question

If $a,b,c$ are different, then the value of $x$ satisfying $\left| \begin{matrix} 0 & x^{2} - a & x^{3} - b \ x^{2} + a & 0 & x^{2} + c \ x^{4} + a & x - c & 0 \end{matrix} ight| = 0$ is

Dr. Abubacker · Accepted Answer

(d)
Since, for $x = 0$, the determinant reduces to the determinant of a skew-symmetric matrix of odd order which is always zero. Hence, $x = 0$ is the solution of the given equation.

Q. If $a,b,c$ are different, then the value of $x$ satisfying $\left| \begin{matrix} 0 & x^{2} - a & x^{3} - b \\ x^{2} + a & 0 & x^{2} + c \\ x^{4} + a & x - c & 0 \end{matrix} \right| = 0$ is

Explanation

Reviewed by Dr. Abubacker

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