Q. If $\left| \begin{matrix} x & 3 & 6 \\ 3 & 6 & x \\ 6 & x & 3 \end{matrix} \right| = \left| \begin{matrix} 2 & x & 7 \\ x & 7 & 2 \\ 7 & 2 & x \end{matrix} \right| = \begin{bmatrix} 4 & 5 & x \\ 5 & x & 4 \\ x & 4 & 5 \end{bmatrix} = 0,$then $x$ is equal to

A) 9
B) $- 9$
C) 0
D) $- 1$
Explanation

(b)
$\left| \begin{matrix}
x & 3 & 6 \\
3 & 6 & x \\
6 & x & 3
\end{matrix} \right| = \left| \begin{matrix}
2 & x & 7 \\
x & 7 & 2 \\
7 & 2 & x
\end{matrix} \right| = \begin{bmatrix}
4 & 5 & x \\
5 & x & 4 \\
x & 4 & 5
\end{bmatrix} = 0$
$\Rightarrow \left| \begin{matrix}
x + 9 & x + 9 & x + 9 \\
3 & 6 & x \\
6 & x & 3
\end{matrix} \right| = \left| \begin{matrix}
9 + x & x + 9 & 9 + x \\
x & 7 & 2 \\
7 & 2 & x
\end{matrix} \right|$
$= \begin{bmatrix}
9 + x & 9 + x & 9 + x \\
5 & x & 4 \\
x & 4 & 5
\end{bmatrix} = 0$
$\Rightarrow (x + 9)\left| \begin{matrix}
1 & 0 & 0 \\
3 & 3 & x - 3 \\
6 & x - 6 & - 3
\end{matrix} \right| = (9 + x)\left| \begin{matrix}
1 & 0 & 0 \\
x & 7 - x & 2 - x \\
7 & - 5 & x - 7
\end{matrix} \right|$
$= (9 + x)\ \left| \begin{matrix}
1 & 0 & 0 \\
5 & x - 5 & - 1 \\
x & 4 - x & 5 - x
\end{matrix} \right|$
$= 0$
$\Rightarrow x + 9 = 0\ \Rightarrow x = - 9$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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