Q. $\left| \begin{array}{r} a - b + c\ \ \ \ \ –a - b + c\ \ \ \ \ \ \ \ \ 1 \\ a + b + 2c\ \ \ \ –a + b + 2c\ \ \ \ \ 2 \\ 3c\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 3c\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 3 \end{array} \right|$ is

A) $6ab$
B) $ab$
C) $12ab$
D) $2ab$
Explanation

(c)
$\left| \begin{array}{r}
a - b + c\ \ \ \ \ –a - b + c\ \ \ \ \ \ \ \ \ 1 \\
a + b + 2c\ \ \ \ –a + b + 2c\ \ \ \ \ 2 \\
3c\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 3c\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 3
\end{array} \right|$
$\left| \begin{array}{r}
2a\ \ \ \ \ \ \ \ \ \ \ \ - 2a\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 0 \\
a + b + 2c\ \ \ \ –a + b + 2c\ \ \ \ \ 2 \\
3c\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 3c\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 3
\end{array} \right|$
[$using\ R_{1} \rightarrow R_{1} + R_{2} - R_{3}\rbrack$
$= 2a( - 3a + 3b + 6c - 6c) + 2a(3a + 3b + 6c - 6c)$
$= 12ab$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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