Q. Determinant $\left| \begin{matrix} b^{2} - ab & b - c & bc - ac \\ ab - a^{2} & a - b & b^{2} - ab \\ bc - ac & c - a & ab - a^{2} \end{matrix} \right|$ is equal to

A) $abc(a + b + c)$
B) $3a^{2}b^{2}c^{2}$
C) 0
D) None of these
Explanation

(c)
Let $\mathrm{\Delta} = \left| \begin{matrix}
b^{2} - ab & b - c & bc - ac \\
ab - a^{2} & a - b & b^{2} - ab \\
bc - ac & c - a & ab - a^{2}
\end{matrix} \right|$
$= (b - a)(b - a)\left| \begin{matrix}
b & b - c & c \\
a & a - b & b \\
c & c - a & a
\end{matrix} \right|$
$= (a - b)^{2}\left| \begin{matrix}
b & b & c \\
a & a & b \\
c & c & a
\end{matrix} \right|$ $(C_{2} \rightarrow C_{2} + C_{3})$
$= 0$ $(\because$ two columns are same)

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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