Q. If $f(x) = \left| \begin{matrix} 1 + a & 1 + ax & 1 + ax^{2} \\ 1 + b & 1 + bx & 1 + {bx}^{2} \\ 1 + c & 1 + cx & 1 + {cx}^{2} \end{matrix} \right|,\$where $a,b,c$ are non-zero constants, then value of $f(10)$is

A) $10\ (b - a)(c - a)$
B) $100\ (b - a)(c - b)(a - c)$
C) $100\ abc$
D) 0
Explanation

(d)
Given, $f(x) = \left| \begin{matrix}
1 + a & 1 + ax & 1 + ax^{2} \\
1 + b & 1 + bx & 1 + {bx}^{2} \\
1 + b & 1 + cx & 1 + {cx}^{2}
\end{matrix} \right|$
$\Rightarrow f(x) = \left| \begin{matrix}
1 + a & a(x - 1) & ax(x - 1) \\
1 + b & b(x - 1) & bx(x - 1) \\
1 + b & c(x - 1) & cx(x - 1)
\end{matrix} \right|$
$= (x - 1)x(x - 1)\left| \begin{array}{r}
1 + a\ \ a\ \ a \\
1 + b\ \ b\ \ b \\
1 + c\ \ c\ \ c
\end{array} \right|$=0
($\therefore two\ columns\ are\ same)$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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