Q. The coefficient of $x$ in $f(x) = \left| \begin{matrix} x & 1 + \sin x & \cos x \\ 1 & \log{(1 + x)} & 2 \\ x^{2} & 1 + x^{2} & 0 \end{matrix} \right|$, $- 1 < x \leq 1$, is

A) 1
B) $- 2$
C) $- 1$
D) 0
Explanation

(b)
Given , $f(x) = \left| \begin{matrix}
x & 1 + \sin x & \cos x \\
1 & \log{(1 + x)} & 2 \\
x^{2} & 1 + x^{2} & 0
\end{matrix} \right|$
$= x\left\{ - 2\left( 1 + x^{2} \right) \right\} - (1 + \sin{x)\left( - 2x^{2} \right) + \cos{x\{ 1 + x^{2} - x^{2}\log{(1 + x)\}}}}$
$= - 2x - 2x^{3} + 2x^{2} + 2x^{2}\sin{x + \cos{x\{ 1 + x^{2} - x^{2}\log{(1 + x)\}}}}$
$\therefore Coefficient\ of\ x\ in\ f(x) = - 2.$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

Want more practice?
Practice Determinants MCQs