Q. If $A = \left\lbrack \begin{array}{r} 3\ \ 5 \\ 2\ \ 0 \end{array} \right\rbrack$and $B = \left\lbrack \begin{array}{r} 1\ \ \ \ \ \ \ \ \ 17 \\ 0\ \ \ - 10 \end{array} \right\rbrack,$then $|AB|$ is equal to

A) 80
B) 100
C) $- 110$
D) 92
Explanation

(b)
$AB = \left\lbrack \begin{array}{r}
3\ \ 5 \\
2\ \ 0
\end{array} \right\rbrack\left\lbrack \begin{array}{r}
1\ \ \ \ \ \ \ \ \ 17 \\
0\ \ \ - 10
\end{array} \right\rbrack = \left\lbrack \begin{array}{r}
3\ \ \ \ \ \ \ \ \ 1 \\
2\ \ \ \ \ \ 34
\end{array} \right\rbrack$
$\Rightarrow \ \ \ \ \ |AB| = \left\lbrack \begin{array}{r}
3\ \ 1 \\
2\ \ 34
\end{array} \right\rbrack = 100$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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