(b)
$AB = \left\lbrack \begin{array}{r}
3\ \ 5 \\
2\ \ 0
\end{array} \right\rbrack\left\lbrack \begin{array}{r}
1\ \ \ \ \ \ \ \ \ 17 \\
0\ \ \ - 10
\end{array} \right\rbrack = \left\lbrack \begin{array}{r}
3\ \ \ \ \ \ \ \ \ 1 \\
2\ \ \ \ \ \ 34
\end{array} \right\rbrack$
$\Rightarrow \ \ \ \ \ |AB| = \left\lbrack \begin{array}{r}
3\ \ 1 \\
2\ \ 34
\end{array} \right\rbrack = 100$