Q. For the function $f(x) = \left\{ \begin{array}{r} \frac{x^{3} - a^{3}}{x - a},\ x \neq a \\ b,\ \ \ \ \ \ \ \ \ x = a \end{array} \right.\$, if $f(x)$ is continuous at $x = a$, then $b$ is equal to

A) $a^{2}$
B) $2a^{2}$
C) $3a^{2}$
D) $4a^{2}$
Explanation

(c)
LHL$= \lim_{x \rightarrow a^{-}}\frac{x^{3} - a^{3}}{x - a} = \lim_{h \rightarrow 0}\frac{(a - h)^{3} - a^{3}}{a - h - a}$
$= \lim_{h \rightarrow 0}\frac{{(a - h - a)\{(a - h)}^{2} + a^{3} + a(a - h)\}}{- h} = 3a^{2}$
Since, $f(x)$ is continuous at $x = a$
$\therefore\ \ \ \ LHL = f(a)$
$\Rightarrow \ \ \ \ 3a^{2} = b$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.