Q. If $f(x) = \left\{ \begin{array}{r} ax^{2} + b,\ \ b \neq 0,\ x \leq 1 \\ x^{2}b + ax + c,\ \ \ x > 1 \end{array} \right.\$, then, $f(x)$ is continuous and differentiable at $x = 1$, if

A) $c = 0,\ a\text{=}2b$
B) $a = b,\ c \in R$
C) $a = b\ ,\ c = 0$
D) $a = b,\ c \neq 0$
Explanation

(a)
Here, $f^{'}(x) = \left\{ \begin{array}{r}
2ax,\ \ b \neq 0,\ x \leq 1 \\
2bx + a,\ \ x > 1
\end{array} \right.\$
Since, $f(X)$ is continuous at $x = 1$
$\therefore\ \ \ \lim_{h \rightarrow 0}\ \ f(x) = \lim_{h \rightarrow 1^{+}}\ f(x)$
$\Rightarrow \ \ \ a + b = b + a + c\ \Rightarrow c = 0$
Also, $f(x)$ is differentiable at $x = 1$
$\therefore\$(LHD at $x = 1$)=(RHD at $x = 1$)
$\Rightarrow \ \ 2a = 2b(1) + a\ \ \Rightarrow \ \ a = 2b$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.