Q. The function $f(x) = \frac{2x^{2} + 7}{x^{3} + 3x^{2} - x - 3}$ is discontinuous for
A) $x = 1$ only
B) $x = 1$ and $x = - 1$ only
C) $x = 1,\ x = - 1,\ x = - 3$ only
D) $x = 1,\ x = - 1,\ x = - 3$ and other values of $x$
Explanation
(c)
Given, $f(x) = \frac{2x^{2} + 7}{\left( x^{2} - 1 \right)(x + 3)}$
Since, at $x = 1,\ - 1,\ - 3,\ \ f(x) = \infty$
Hence, function is discontinuous
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.