If$f(x) = ae^{|x|} + b|x|^{2}$; $a,\ b\ \in R$ and $f(x)$ is differentiable at $x = 0$. Then $a$ and $b$ are

Question

Dr. Abubacker · Accepted Answer

(a)
Given, $f(x) = ae^{|x|} + b\ |x|^{2}$
We know $e^{|x|}$ is not differentiable at $x = 0$ and $|x|^{2}$ is differentiable at $x = 0$
$	herefore\ \ f(x)$ is differentiable at $x = 0$, if $a = 0$ and $b \in R$

Q. If$f(x) = ae^{|x|} + b|x|^{2}$; $a,\ b\ \in R$ and $f(x)$ is differentiable at $x = 0$. Then $a$ and $b$ are

Explanation

Reviewed by Dr. Abubacker

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