Let $f(x) = ||x| - 1|$, then points where $f(x)$ is not differentiable, is/(are)

Question

Dr. Abubacker · Accepted Answer

(a)
Using graphical transformation
[image:5_image11.emf]
As, we know the function is not differentiable at6 sharp edges and in figure (iii) $y = \left| |x| - 1 ight|$ we have 3 sharp edges at $x = - 1,\ 0,\ 1$
$	herefore f(x)$ is not differentiable at $\{ 0,\  \pm 1\}$

Q. Let $f(x) = ||x| - 1|$, then points where $f(x)$ is not differentiable, is/(are)

Explanation

Reviewed by Dr. Abubacker

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