Let $f:R \longrightarrow R\$be defined by $f(x) = \left\{ \begin{array}{r} k - 2x,\ \ if\ x \leq - 1 \ 2x + 3,\ \ ifx - 1\ \end{array} ight.\$ If $f$has a local minimum at $x = - 1,\ then\ a\ possible\ value\ of\ k\ is$

Question

Let $f:R \longrightarrow R\$be defined by $f(x) = \left\{ \begin{array}{r} k - 2x,\ \ if\ x \leq - 1 \ 2x + 3,\ \ ifx > - 1\ \end{array} ight.\$ If $f$has a local minimum at $x = - 1,\ then\ a\ possible\ value\ of\ k\ is$

Dr. Abubacker · Accepted Answer

(d)
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$\because k + 2 \geq 1$
$	herefore k \leq - 1$

Q. Let $f:R \longrightarrow R\$be defined by $f(x) = \left\{ \begin{array}{r} k - 2x,\ \ if\ x \leq - 1 \\ 2x + 3,\ \ ifx > - 1\ \end{array} \right.\$ If $f$has a local minimum at $x = - 1,\ then\ a\ possible\ value\ of\ k\ is$

Explanation

Reviewed by Dr. Abubacker

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