(d) Since, $f(x) = x\ e^{1 - x}$ $f^{'}(x) = - xe^{1 - x} + e^{1 - x}$ $= e^{1 - x}(1 - x)$ $\Rightarrow \ \ \ f^{'}(x) < 0,\ \ \ \forall\ (1,\ \infty)$
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.