(b) Given, $f(x) = \frac{x}{3} + \frac{3}{x} \Rightarrow f^{''}(x) = \frac{1}{3} - \frac{3}{x^{2}}$ Put $f^{''}(x) = 0\ \Rightarrow x = \pm 3$ [image:6_image11.emf] Thus, $f(x)$is decreasing in the interval $( - 3,3).$
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Ph.D. in Physics with 19+ years of teaching experience.