(c) $f(x) = \cot^{- 1}{x + x}$ $\Rightarrow f^{'}(x) = - \frac{1}{1 + x^{2}} + 1$ $= \frac{x^{2}}{1 + x^{2}},\ clearly,\ f’(x) >$for all$x$. So, $f(x)$ increases in ($- \infty,\infty$).
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.