A missile is fired from the ground level rises $x$ metres vertically upwards in $t$ seconds where $x = 100t - \frac{25}{2}t^{2}.$The maximum height reached is

Question

Dr. Abubacker · Accepted Answer

(a)
On differentiating given equation w. r. t. $x,\$we get
$\frac{dx}{dt} = 100 - \frac{25}{2}$.(2t)=100-25t
At maximum height, velocity $\frac{dx}{dt} = 0$
$	herefore\ \ \ \ \ \ \ \ 100 - 25t = 0\ \ \  \Rightarrow \ \ \ t = 4$
$	herefore\ \ \ x = 100 	imes 4 - \frac{25 	imes 16}{2} = 200m$

Q. A missile is fired from the ground level rises $x$ metres vertically upwards in $t$ seconds where $x = 100t - \frac{25}{2}t^{2}.$The maximum height reached is

Explanation

Reviewed by Dr. Abubacker

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