For a given integer $k$, in the interval $\left\lbrack 2\pi k + \frac{\pi}{2},\ 2\pi k - \frac{\pi}{2} \right\rbrack$ the graph of $\sin x$ is

Question

Dr. Abubacker · Accepted Answer

(a)
Since, $2\pi k - \frac{\pi}{2} \leq$ sin$x \leq 2\pi k + \frac{\pi}{2}$
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For $k = 0$
$- \frac{\pi}{2} < \sin{x < \frac{\pi}{2}}$
Which increase from$- 1\ to\ 1.$
Similarly, for other values of k it is increase from $- 1\ to\ 1.$

Q. For a given integer $k$, in the interval $\left\lbrack 2\pi k + \frac{\pi}{2},\ 2\pi k - \frac{\pi}{2} \right\rbrack$ the graph of $\sin x$ is

Explanation

Reviewed by Dr. Abubacker

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