Q. The distance $'s^{'}$meters covered by a body in t seconds,is given by $s = 3t^{2} - 8t + 5.$ The body will stop after
A) 1 $s$
B) $\frac{3}{4}s$
C) $\frac{4}{3}s$
D) 4 $s$
Explanation
(c)
Given, $s = 3t^{2} - 8t + 5$
and $v = \frac{ds}{dt} = 6t - 8$
The body will be stopped when velocity is zero
$\Rightarrow \ \ 6t - 8 = 0\ \ \Rightarrow \ \ \ t = \frac{4}{3}s$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.