The distance travelled $s(in\ meteres)$ by a particle in $t\$second is given by$,s = t^{3} + 2t^{2} + t.$The speed of the particle after 18 will be

Question

Dr. Abubacker · Accepted Answer

(a)
Given, $s = t^{3} + 2t^{2} + t$
$\Rightarrow \ \ \ v = \frac{ds}{dt} = 3t^{2} + 4t + 1$
Speed of the particle after 1 s
$v_{(t = 1)} = \left( \frac{ds}{dt} ight)_{(t = 1)}$
$= 3 	imes 1^{2} + 4 	imes 1 + 1 = 3 + 5 = 8$ cm/s

Q. The distance travelled $s(in\ meteres)$ by a particle in $t\$second is given by$,s = t^{3} + 2t^{2} + t.$The speed of the particle after 18 will be

Explanation

Reviewed by Dr. Abubacker

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