Q. If $g(x) = \min{(x,\ x^{2})}$, where $x$ is real number, then
A) $g(x)$ is an increasing function
B) $g(x)$ is a decreasing function
C) $f(x)$ is a constant function
D) $g(x)$ is a continuous function except at $x = 0$
Explanation
(a)
$\because g(x) = \min\left( x,\ x^{2} \right)$
$\therefore\ \ g(x)$ is an increasing function
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.