Q. The distance covered by a particle in $t$ second is given by $x = 3 + 8t - 4t^{2}.\$After 1s its velocity will be
A) 0 unit
B) 3 units
C) 4 units
D) 7 units
Explanation
(a)
Given , $x = 3 + 8t - 4t^{2},$
On differentiating, w. r. t. x, we get
$v = \frac{dx}{dt} = 8 - 8t$
At $t = 1,\ v = 8 - 8 = 0\$unit
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.