Q. If the error committed in measuring the radius of the circle is 0.05%, then the corresponding error in calculating the area is
A) 0.05%
B) 0.0025%
C) 0.25%
D) 0.1%
Explanation
(d)
$\because\ A = \pi r^{2}$
$\Rightarrow \ \ \log{A = log\pi + 2\log r}$
$\Rightarrow \ \frac{\mathrm{\Delta}A}{A}100 = 2 \times \frac{\mathrm{\Delta}r}{100}$
$\ = 2 \times 0.05$
$\ = 0.1\%$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.