(c) Slope of the normal$= - \frac{1}{\left( \frac{dy}{dx} \right)}$ This is parallel to $x$-axis $\Rightarrow \ \ - \frac{1}{\left( \frac{dy}{dx} \right)} = 0\ \ \ \Rightarrow \ \frac{dx}{dy} = 0$
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.