(c) Let$f(x) = x^{2} - x + 1$ $\Rightarrow f^{'}(x) = 2x - 1$ $\Rightarrow f^{'}(0) = - 1$ And $f^{'}(1) = 1$ Thus, function is neither increasing nor decreasing.
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Ph.D. in Physics with 19+ years of teaching experience.