(c) Given that$\ f(x) = sin\ x - bx + c$ $\therefore f^{'}(x) = \cos{x - b}$ For decreasing, $f^{'}(x) < 0,for\ all\ x \in R$. $\Rightarrow \cos{x < b\ for\ all\ x \in R \Rightarrow b > 1.}$
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