Q. If $g(x) = \min{(x,\ x^{2})}$ where $x$ is real number, then

A) $g(x)$ is an increasing function
B) $g(x)$ is a decreasing function
C) $g(x)$is a constant function
D) $g(x)$ is a continuous function except at $x = 0$
Explanation

(a)
$\therefore g(x) = min(x,x^{2})$
[image:6_image22.emf]
It is clear from the graph that g(x) is an increasing function

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.