Q. The number of critical points of $f(x) = |x|(x - 1)(x - 2)(x - 3)$ is

A) 1
B) 2
C) 3
D) 4
Explanation

(d)
We have, $f(x) = |x|(x - 1)(x - 2)(x - 3)$
$= \left\{ \begin{array}{r}
x(x - 1)(x - 2)(x - 3),\ x \geq 0 \\
- x(x - 1)(x - 2)(x - 3),\ \ x < 0
\end{array} \right.\$
[image:6_image23.emf]
It is clear from the figure that, there are four critical points
$ie,\ 0,\ \alpha,\ \beta,\ \gamma\$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.