Explanation

(d)
Given curve is $y = 2x^{2} - x + 1$ …(i)
$\Rightarrow \ \ \ \frac{dy}{dx} = 4x - 1$
Since, tangent to the curve is parallel to the given line$y = 3x + 9$. Then, slopes will be equal
$\therefore\ \ \ \ \ 4x - 1 = 3$
$\Rightarrow \ \ \ \ x = 1$
From Eq. (i), $y = 2(1)^{2} - 1 + 1 = 2$
Hence, required point is (1, 2)