Q. A stone is thrown vertically upwards and the height$\ x$ ft reached by the stone in t seconds is given by $x = 80t - 16t^{2}.\$The stone reaches the maximum height in

A) 2s
B) 2.5s
C) 3s
D) 1.5s
Explanation

(b)
Given, $x = 80t - 16t^{2}$
$\Rightarrow \ \ \ \ \ \ \ \ \ \ \ \ \ \frac{dx}{dt} = 80 - 32t$
At maximum height$\frac{dx}{dt} = 0$
$\therefore\ \ \ t = 25s$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.