Q. $\int_{0}^{\pi/2}{\frac{\sin^{2}x}{\sin^{2}{x + \cos^{2}x}}dx}$ is equal to

A) $\frac{\pi}{4}$
B) $2\pi$
C) $\pi^{2}$
D) $\frac{1}{2}\pi^{2}$
Explanation

(a)
Let $I = \int_{0}^{\pi/2}{\frac{\sin^{2}x}{\sin^{2}{xcos^{2}x}}dx}$ …(i)
$\Rightarrow I = \int_{0}^{\pi/2}{\frac{\cos^{2}x}{\sin^{2}{x + \cos^{2}x}}dx\ \ \ \ \ \ldots(ii)}$
On adding Eqs. (i) and(ii), we get
$2I = \int_{0}^{\pi/2}{1\ dx = \lbrack x\left. \ \ \right\rbrack_{0}^{\pi/2}} = \frac{\pi}{2}$
$\Rightarrow \ I = \frac{\pi}{4}$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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