Q. $\int_{- \pi/2}^{\pi/2}{\frac{dx}{1 + \cos x}is}$ equal to

A) 0
B) 1
C) 2
D) 3
Explanation

(c)
Let $I = \int_{- \pi/2}^{\pi/2}\frac{dx}{2\cos^{2}\frac{x}{2}}$
$= \int_{0}^{\pi/2}{\sec^{2}{\frac{x}{2}dx = \left\lbrack 2\tan\frac{x}{2} \right\rbrack_{0}^{\pi/2}} = 2}$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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