Q. The value of the integral $\int_{- a}^{a}\frac{x{e^{x}}^{2}}{1 + x^{2}}dx$is
A) ${e^{a}}^{2}$
B) 0
C) ${e^{- a}}^{2}$
D) $a$
Explanation
(b)
Since, $\frac{x{e^{x}}^{2}}{1 + x^{2}}$is an odd function
$\therefore\int_{- a}^{a}{\frac{x{e^{x}}^{2}}{1 + x^{2}}dx = 0}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.