Q. $\int_{- 1}^{1}{\frac{17x^{5} - x^{4} + 29x^{3} - 31x + 1}{x^{2} + 1}dx\ is}$

A) $\frac{4}{5}$
B) $\frac{5}{4}$
C) $\frac{4}{3}$
D) $\frac{3}{4}$
Explanation

(c)
Let $I = \int_{- 1}^{1}{\frac{17x^{5} + 29x^{3} - 31\ x}{x^{2} + 1}dx - \int_{- 1}^{1}{\frac{x^{4} - 1}{x^{2} + 1}dx}}$
$= 0 - 2\int_{0}^{1}{\frac{\left( x^{2} - 1 \right)(x^{2} + 1)}{(x^{2} + 1)}dx}$
$= - 2\left\lbrack \left( \frac{x^{3}}{3} - x \right) \right\rbrack_{0}^{1} = \frac{4}{3}$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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