Q. $\int_{- 2}^{2}{|x|}\ dx\$is equal to

A) 0
B) 1
C) 2
D) 4
Explanation

(d)
$\int_{- 2}^{2}{|x|dx = - \int_{- 2}^{0}{x\ dx + \int_{0}^{2}{x\ dx}}}$
$= - \left\lbrack \frac{x^{2}}{2} \right\rbrack_{- 2}^{0} + \left\lbrack \frac{x^{2}}{2} \right\rbrack_{0}^{2}$
$= - (0 - 2) + (2 - 0) = 4$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

Want more practice?
Practice Integrals MCQs