Q. The value of $I = \int_{- \pi/2}^{\pi/2}{|\sin{x|\ dx}is}$
A) 0
B) 2
C) $- 2$
D) $- 2 < I < 2$
Explanation
(b)
$\int_{- \frac{\pi}{2}}^{\frac{\pi}{2}}{|\sin{x|dx}}$
$= 2\int_{0}^{\frac{\pi}{2}}{\sin{x\ dx = - 2\lbrack\cos{x\left. \ \ \right\rbrack_{0}^{\frac{\pi}{2}}}}}$
$= - 2\left( \cos{\frac{\pi}{2} - \cos 0} \right) = 2$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.