Q. The value of $\int_{–\pi/2}^{\pi/2}{(x^{3}} + x\cos{x + \tan^{5}{x + 1)dx}}$is equal to

A) 0
B) 2
C) $\pi$
D) None of these
Explanation

(c)
Let $I = \int_{- \pi/2}^{\pi/2}{(x^{3} + x\cos{x + \tan^{5}{x + 1)dx}}}$
Since, $x^{3},x\cos{x\ and\tan^{5}{x\ are\ odd\ functions,}}$
$therefore$
$I = \int_{- \pi/2}^{\pi/2}{1dx = \lbrack x\rbrack_{- \pi/2}^{\pi/2} = \pi}$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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