Q. $\int_{- 2}^{2}{\left| \lbrack x\rbrack \right|\ dx}$ is equal to

A) 1
B) 2
C) 3
D) 4
Explanation

(d)
$\int_{- 2}^{2}{\left| \lbrack x\rbrack \right|dx}$
$= \int_{- 2}^{- 1}{\left| \lbrack x\rbrack \right|dx} + \int_{- 1}^{0}{\left| \lbrack x\rbrack \right|dx} + \int_{0}^{1}{\left| \lbrack x\rbrack \right|dx} + \int_{1}^{2}{\left| \lbrack x\rbrack \right|dx}$
$= \int_{- 2}^{- 1}{2\ dx +}\int_{- 1}^{0}{1\ dx +}\int_{0}^{1}{0\ dx +}\int_{1}^{2}{1\ dx}$
$= 2\lbrack x\rbrack_{- 2}^{- 1} + \lbrack x\rbrack_{- 1}^{0} + 0 + \lbrack x\rbrack_{1}^{2}$
$= 2( - 1 + 2) + (0 + 1) + (2 - 1) = 2 + 1 + 1 = 4$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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