(a) Given, $f(x) = f(a + x)$and $\int_{0}^{a}{f(x)dx = k}$ $\int_{a}^{na}{f(x)dx = n\int_{0}^{a}{f(x) = nk}}$ $\lbrack\because f(x)$ is periodic function]
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Ph.D. in Physics with 19+ years of teaching experience.