Q. If $f(x) = f(a + x)$and $\int_{0}^{a}{f\ (x)dx = k,\ }then\int_{0}^{na}{f(x)dx}$ is equal to

A) $nk$
B) $(n - 1)k$
C) $(n + 1)k$
D) 0
Explanation

(a)
Given, $f(x) = f(a + x)$and $\int_{0}^{a}{f(x)dx = k}$
$\int_{a}^{na}{f(x)dx = n\int_{0}^{a}{f(x) = nk}}$
$\lbrack\because f(x)$ is periodic function]

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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