(a)
Let $I = \int_{1}^{x}{\frac{\log{(x^{2})}}{x}dx = 2\int_{1}^{x}{\log{x.\frac{1}{x}dx}}}$
Put $\log{x = t\ \Rightarrow \ \frac{1}{x}dx = dt}$
$\therefore I = 2\int_{0}^{\log x}{t\ dt = 2\left\lbrack \frac{t^{2}}{2} \right\rbrack_{0}^{\log{x\ }} =}\left( \log x \right)^{2}$