Q. If $\int_{- 1/2}^{1/2}{\cos{x\log\left( \frac{1 + x}{1 - x} \right)dx = k.\log 2}}$, then $k$ equals

A) 0
B) $- 1$
C) $- 2$
D) $\frac{1}{2}$
Explanation

(a)
$\cos\ x\ \log\left( \frac{1 + x}{1 - x} \right)$is an odd function
$\therefore\ \int_{- 1/2}^{1/2}{\cos{x\log\ \left( \frac{1 + x}{1 - x} \right)dx = 0}}$
$\therefore\ k = 0$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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