Q. The net requirement of assimilatory power for the formation of 6 hexose molecules in maize plant is
A) 72 ATP, 48 NADPH
B) 90 ATP, 60 NADPH
C) 108 ATP, 72 NADPH
D) 180 ATP, 72 NADPH
Explanation
$C_{4}$-plants (maize) require 30 ATP and 12 NADPH for synthesis of one hexose molecule. Therefore, synthesis of six hexose molecules requires 180 ATP and 72 NADPH.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.