Q. $\int_{}^{}{\frac{x^{2} - 1}{(x^{2} + 1)\sqrt{x^{4} + 1}}\ dx}$ is equal to
A) $\sec^{- 1}{\left( \ \frac{x^{2} + 1}{x\sqrt{2}}\ \right) + c}$
B) $\frac{1}{2}\sec^{- 1}{\left( \ \frac{x^{2} + 1}{\sqrt{2}}\ \right) + c}$
C) $\frac{1}{2}\sec^{- 1}{\left( \ \frac{x^{2} + 1}{x\sqrt{2}}\ \right) + c}$
D) None of these
Explanation
The correct answer is Option C: $\frac{1}{2}\sec^{- 1}{\left( \ \frac{x^{2} + 1}{x\sqrt{2}}\ \right) + c}$.
A detailed explanation for this question is being prepared.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.