Q. $\int_{}^{}\frac{d\ (\cos{\theta)}}{\sqrt{1 - \cos^{2}\theta}}$ is equal to
A) $\cos^{- 1}{\theta + c}$
B) $\theta + c$
C) $\sin^{- 1}{\theta + c}$
D) $\sin^{- 1}{(\cos{\theta)} + c}$
Explanation
(d)
$\int_{}^{}\frac{d\ (\cos{\theta)}}{\sqrt{1 - \cos^{2}\theta}} = \sin^{- 1}{(\cos{\theta) + c}}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.